AREA AND PERIMETER WORD PROBLEMS - onlinemath4all AREA AND PERIMETER WORD PROBLEMS. Problem 1 : The length of a rectangle is 4 less than 3 times its width. If its perimeter is 32 cm, then find the area of the rectangle. Solution : Let x be the width of the rectangle. Then, its length is (3x - 4). Perimeter of the rectangle is 32 cm. 2 (l + w) = 32.